Friday, June 25th, 2010 at 9:12 am , filed under Wimbledon by Terry Lawrence
Justine Henin vs Nadia Petrova Wimbledon 2010: Justine Henin will be facing up Nadia Petrova in the third round of Wimbledon 2010 on June 25th, 2010.
Match Venue: London.
Match Time: 13.00 GMT.
Players Report:
On Friday, Justine Henin will meet Nadia Petrova in the third round of Wimbledon 2010 at Center Court.
Justine Henin is an Belgium tennis player. In ATP rankings, she is currently ranked World No.16. In the first round of Wimbledon 2010, Justine Henin won against Anastasija Sevastova with 6-4 and 6-3. In the second round of Wimbledon 2010, she has defeated Kristina Barrois with 6-3 and 7-5.
In the first round of UNICEF Open, she won against Angelique Kerber with 6-4 and 6-2. In the second round of UNICEF Open, Justine Henin has defeated Roberta Vinci with 6-3 and 6-3. In the quarter finals of UNICEF Open, Kristina Barrois lost against 5-7 and 3-6.
In the semi finals of UNICEF Open, Justine Henin won against Alexandra Dulgheru with 6-2 and 6-2. In the finals of UNICEF Open, she has defeated Andrea Petkovic with 3-6, 6-3 and 6-4.
Nadia Petrova is an Russian tennis player. In ATP rankings, she is currently ranked World No.13 in singles and World No.11 in doubles. In the first round of Wimbledon 2010, Nadia Petrova won against Tatjana Malek with 6-4 and 6-3. In the second round of Wimbledon 2010, she has defeated Yung-Jan Chan with 6-3 and 6-4.
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